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The unit of ebillioscopic constant is...

The unit of ebillioscopic constant is

A

K kg `mol^(-1) or K("molality")^(-1)`

B

mol kg `K^(-1)or K^(-1)("molality")`

C

kg `mol^(-1)K^(-1)or K^(-1)("molality")^(-1)`

D

K `mol kg^(-1)or K ("molality")`

Text Solution

Verified by Experts

The correct Answer is:
A
As we know from elevation in boiling point that
`DeltaT_(b)K_(b)m`
`K_(b)=(DeltaT_(b))/(m)`
Unit of `K_(b)=("unit of "DeltaT_(b))/("unit of"m)=(K)/("molality")`
`=(K)/(molkg^(1))=Kmol^(-1)kg`
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