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Which of the following statements is FAL...

Which of the following statements is FALSE ?

A

Two different solutions of sucrose of same molality prepared in different solvents will have the same deperssion in freezing point.

B

The osmotic pressure of a solution is given by the equalition `pi`=CRT (where, C is the molarity of the solution)

C

Decreasing order of osmotic pressure for 0.01 M aqueous solutions of barium chloride, patassium chloride, acetic acid and sucrose is
`" "BaCl_(2) gtKClgt CH_(3)COOHgt` sucrose

D

According to Raoult's law, the vapour pressure exerted by a valatiloe component of a solution is directly proportional to its mole fraction in the solution

Text Solution

AI Generated Solution

The correct Answer is:
To determine which statement is false, we will analyze each option provided in the question step by step. ### Step 1: Analyze Option 1 **Statement:** Two different solutions of sucrose of the same molality prepared in different solvents will have the same depression in freezing point. **Analysis:** - The depression in freezing point (\( \Delta T_f \)) is given by the formula: \[ \Delta T_f = K_f \cdot m \cdot i \] where \( K_f \) is the cryoscopic constant of the solvent, \( m \) is the molality, and \( i \) is the van't Hoff factor. - For sucrose, the van't Hoff factor \( i = 1 \) because it does not dissociate in solution. - While the molality \( m \) is the same for both solutions, the cryoscopic constant \( K_f \) will differ for different solvents. - Therefore, the depression in freezing point will not be the same for both solutions since \( K_f \) varies with the solvent. **Conclusion:** This statement is FALSE. ### Step 2: Analyze Option 2 **Statement:** The osmotic pressure of a solution is given by \( \pi = CRT \). **Analysis:** - The formula for osmotic pressure is indeed given by: \[ \pi = iCRT \] where \( i \) is the van't Hoff factor. However, the statement simplifies to \( \pi = CRT \) which is technically correct if \( i = 1 \) (non-electrolyte solutions). - Since this statement holds true for non-electrolytes, we consider it correct. **Conclusion:** This statement is TRUE. ### Step 3: Analyze Option 3 **Statement:** Decreasing order of osmotic pressure for 0.01 M aqueous solutions of barium chloride, potassium chloride, acetic acid, and sucrose. **Analysis:** - The osmotic pressure is calculated as: \[ \pi = iCRT \] - For barium chloride (BaCl2), \( i = 3 \) (dissociates into Ba²⁺ and 2 Cl⁻). - For potassium chloride (KCl), \( i = 2 \) (dissociates into K⁺ and Cl⁻). - For acetic acid (CH3COOH), \( i \) is less than 2 due to partial dissociation (typically around 1.2). - For sucrose, \( i = 1 \) (non-electrolyte). - Thus, the order of osmotic pressure from highest to lowest is: BaCl2 > KCl > CH3COOH > Sucrose. **Conclusion:** This statement is TRUE. ### Step 4: Analyze Option 4 **Statement:** According to Raoult's law, the vapor pressure exerted by a volatile component of a solution is directly proportional to its mole fraction in the solution. **Analysis:** - Raoult's law states that the vapor pressure of a component in a solution is directly proportional to its mole fraction: \[ P_i = X_i \cdot P_i^0 \] where \( P_i \) is the vapor pressure of the component in the solution, \( X_i \) is the mole fraction, and \( P_i^0 \) is the vapor pressure of the pure component. - This statement is a correct representation of Raoult's law. **Conclusion:** This statement is TRUE. ### Final Conclusion After analyzing all the options, we conclude that the FALSE statement is: **Option 1:** Two different solutions of sucrose of the same molality prepared in different solvents will have the same depression in freezing point. ---

To determine which statement is false, we will analyze each option provided in the question step by step. ### Step 1: Analyze Option 1 **Statement:** Two different solutions of sucrose of the same molality prepared in different solvents will have the same depression in freezing point. **Analysis:** - The depression in freezing point (\( \Delta T_f \)) is given by the formula: \[ ...
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