On the basic of information given below mark the Correct option .Information:
(P)In bromoethane and choroethane mixture intermolar interactions of A.A and B.B is nearly same as A .B type intersections.
(Q) In ethanol and acetone mixture A.A or B.B type inetermolecular interaction are stronger than A.B type interactions.
(R) In chloroform and acetone mixture A.A or B.B type intermolecular interactions are weaker than A. B type interactions.

Options

A. (a) Solution (ii) and (iii) will follow Raoult's law
B. (b) Solution (i) will follow Raoult's law
C. (c) Solution (ii) will show negative deviation from Raoult's law
D. (d) Solution (iii) will show positive deviation from Raoult's law

Explanation

To solve the question, we will analyze each statement (P, Q, and R) and determine their validity based on the principles of solutions and intermolecular interactions.

### Step-by-Step Solution:

1. **Analyzing Statement P:**
- **Statement:** In bromoethane and chloroethane mixture, intermolecular interactions of A.A and B.B are nearly the same as A.B type interactions.
- **Interpretation:** This suggests that the mixture behaves ideally, meaning that the interactions between like molecules (A.A and B.B) are similar to those between unlike molecules (A.B).
- **Conclusion:** This indicates that the mixture follows Raoult's law, which is characteristic of ideal solutions.
- **Validity:** **True**. Statement P is valid.

2. **Analyzing Statement Q:**
- **Statement:** In ethanol and acetone mixture, A.A or B.B type intermolecular interactions are stronger than A.B type interactions.
- **Interpretation:** If A.A and B.B interactions are stronger than A.B interactions, it implies that the A.B interactions are weaker, leading to a higher vapor pressure than expected. This indicates a positive deviation from Raoult's law.
- **Conclusion:** This means that the mixture does not behave ideally and shows positive deviation.
- **Validity:** **True**. Statement Q is valid.

3. **Analyzing Statement R:**
- **Statement:** In chloroform and acetone mixture, A.A or B.B type intermolecular interactions are weaker than A.B type interactions.
- **Interpretation:** If A.A and B.B interactions are weaker than A.B interactions, this suggests that the A.B interactions are stronger, leading to a lower vapor pressure than expected. This indicates a negative deviation from Raoult's law.
- **Conclusion:** This means that the mixture does not behave ideally and shows negative deviation.
- **Validity:** **True**. Statement R is valid.

### Summary of Validity:
- Statement P: True (Ideal solution, follows Raoult's law)
- Statement Q: True (Positive deviation)
- Statement R: True (Negative deviation)

### Correct Option:
Based on the analysis, the correct option is **B** (only statement P follows Raoult's law).