On the basis of information given below mark the correct option.
Information : On adding acetone to methanol some of the hydrogen bonds between methanol molecules breaks.

Options

A. At specific composition methanol-acetone mixture will from minimu boiling azeotrope and will show positive deviationfrom Raoult'a law
B. At specific composition methonal-acetone mixture will from maximum boiling azerotrope and will show positive deviation from Raoult's law
C. At specific composition methanol-acetone mixture will from minmum boiling azerotrope and will show negative deviation from Raoult's law
D. At specific composition methanol-acetone mixture will from maximum boiling azeotrope and will show negative deviation from Raoult's law

Explanation

To solve the question based on the provided information, we will analyze the behavior of methanol and acetone when mixed together, focusing on the hydrogen bonding and the resulting effects on boiling point and vapor pressure.

### Step-by-Step Solution:

1. **Understand the Components**:
- Methanol (CH3OH) is a polar molecule that can form hydrogen bonds with other methanol molecules.
- Acetone (CH3COCH3) is also a polar molecule but does not form hydrogen bonds with itself; it primarily exhibits Van der Waals forces.

2. **Identify the Interaction**:
- When acetone is added to methanol, some of the hydrogen bonds between methanol molecules break. This is due to the presence of acetone, which disrupts the hydrogen bonding network of methanol.

3. **Analyze the Types of Interactions**:
- In pure methanol, the interactions are primarily hydrogen bonds (B-B interactions).
- In pure acetone, the interactions are weaker Van der Waals forces (A-A interactions).
- When mixed, the interactions become A-B (between acetone and methanol), which are weaker than the B-B interactions.

4. **Consider the Effect on Boiling Point**:
- The breaking of hydrogen bonds in methanol due to the presence of acetone leads to a decrease in the overall strength of interactions in the mixture.
- As a result, the boiling point of the methanol-acetone mixture (AB) will be lower than that of pure methanol (BB) and pure acetone (AA).

5. **Azeotropic Behavior**:
- The mixture of methanol and acetone forms a minimum boiling azeotrope. This means that at a specific composition, the boiling point of the mixture is lower than that of either component alone.
- Azeotropes cannot be separated by simple distillation due to their unique vapor-liquid equilibrium.

6. **Deviation from Raoult's Law**:
- The mixture shows positive deviation from Raoult's Law, which means that the vapor pressure of the mixture is higher than expected based on the individual components' vapor pressures.
- This occurs because the interactions between acetone and methanol (A-B) are weaker than the interactions in pure methanol (B-B), leading to a higher tendency for molecules to escape into the vapor phase.

7. **Conclusion**:
- Based on the analysis, the correct option is:
- **A**: At specific composition, the methanol-acetone mixture will form a minimum boiling azeotrope and will show positive deviation from Raoult's Law.