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In the form of dichromate, Cr(VI) is a s...

In the form of dichromate, Cr(VI) is a strong oxidising agent in acidic medium but Mo(VI) in `Mo0_(3)` and W(VI) in `W0_(3)` are not because

A

Cr (VI) is more stable than Mo(VI) and W(VI).

B

Mo (VI) and W (VI) are more stable than Cr(VI).

C

Higher oxidation states of heavier members of group-6 of transition series are more stable.

D

Lower oxidation states of heavier members of group-6 of transition series are more satble.

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To answer the question, we need to analyze the oxidation states of chromium, molybdenum, and tungsten, and understand why Cr(VI) acts as a strong oxidizing agent while Mo(VI) and W(VI) do not. ### Step-by-Step Solution: 1. **Understanding Oxidizing Agents**: - An oxidizing agent is a substance that gains electrons in a chemical reaction and is reduced in the process. Strong oxidizing agents are typically less stable in their higher oxidation states. 2. **Oxidation States of Chromium, Molybdenum, and Tungsten**: - Chromium (Cr) in the form of dichromate (Cr2O7^2-) is in the +6 oxidation state (Cr(VI)). - Molybdenum (Mo) in MoO3 is in the +6 oxidation state (Mo(VI)). - Tungsten (W) in WO3 is also in the +6 oxidation state (W(VI)). 3. **Stability of Higher Oxidation States**: - In the case of chromium, the +6 oxidation state is less stable compared to the +6 oxidation states of molybdenum and tungsten. This is due to the fact that chromium is a lighter element and has a higher tendency to be reduced. 4. **Heavier Elements and Stability**: - Molybdenum and tungsten, being heavier elements, have their +6 oxidation states more stabilized due to their electronic configurations. The energy difference between the s and d orbitals is smaller in heavier elements, allowing them to maintain their higher oxidation states more effectively. 5. **Conclusion**: - Therefore, Cr(VI) is a strong oxidizing agent because it is less stable in its +6 state compared to Mo(VI) and W(VI), which are more stable and do not act as oxidizing agents. ### Final Answer: Cr(VI) is a strong oxidizing agent in acidic medium because it is less stable than Mo(VI) and W(VI), which are more stable in their higher oxidation states.

To answer the question, we need to analyze the oxidation states of chromium, molybdenum, and tungsten, and understand why Cr(VI) acts as a strong oxidizing agent while Mo(VI) and W(VI) do not. ### Step-by-Step Solution: 1. **Understanding Oxidizing Agents**: - An oxidizing agent is a substance that gains electrons in a chemical reaction and is reduced in the process. Strong oxidizing agents are typically less stable in their higher oxidation states. 2. **Oxidation States of Chromium, Molybdenum, and Tungsten**: ...
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NCERT EXEMPLAR ENGLISH-D AND F-BLOCK ELEMENTS-Short Answer Type Question
  1. In the form of dichromate, Cr(VI) is a strong oxidising agent in acidi...

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  2. Why does copper not replace hydrogen from acids?

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  3. Why E^(-) values for Mn, Ni and Zn are more negative than expected?

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  4. Why first ionisation enthalpy of Cr is lower than that of Zn?

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  5. Transition elements show high melting points. Why?

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  6. When Cu^(2+) ion is treated with KI, a white precipitate is formed. Ex...

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  7. Out of Cu(2)Cl(2) and CuCl(2), which is more stable and why?

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  8. When a brown compound of manganese (A) is treated with HCl it gives a ...

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  9. Although fluorine is more electronegative than oxygen, but the ability...

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  10. Although Cr^(3+) and Co^(2+) ions have same number of unpaired electro...

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  11. Ionisation enthalpies of Ce, Pr and Nd are higher than Th, Pa and U. W...

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  12. Although Zr belongs to 4d and Hf belongs to 5d transition series but i...

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  13. Cerium shows oxidation state of +4 because

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  14. Explain why does colour of KMnO(4) disappear when oxalic acid is added...

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  15. When orange solution containing Cr(2)O(7)^(2-) ion is treated with an ...

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  16. A solution of KMnO(4) on reduction yields either a colourless solution...

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  17. The second and third rows of transition elements resemble each other m...

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  18. E^(Theta) of Cu is +0.34V while that of Zn is -0.76 V. Explain.

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  19. The halides of transition elements become more covalent with increasin...

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  20. While filling up of electrons in the atomic orbitals, the 4s orbital i...

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  21. Reactivity of transition elements decreases almost regularly from Sc t...

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