When `Cu^(2+)` ion is treated with KI, a white precipitate is formed. Explain the reaction with the help of chemical equation.

Explanation

To explain the reaction between the copper(II) ion (Cu²⁺) and potassium iodide (KI), we can break down the process step by step.

### Step 1: Understanding the Reactants
- **Copper(II) ion (Cu²⁺)**: This is a cation formed when copper loses two electrons.
- **Potassium iodide (KI)**: This is an ionic compound that dissociates in solution to give potassium ions (K⁺) and iodide ions (I⁻).

### Step 2: Reaction Setup
When Cu²⁺ ions are introduced to a solution containing iodide ions (I⁻), a reaction occurs.
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