A particle executing SHM has a maximum speed of `30 cm//s` and a maximum acceleration of `60 cm/s^(2)` . The period of oscillation is

Options

A. `pisec`
B. `(pi)/(2)sec`
C. `2pisec`
D. `(pi)/(t)sec `

Explanation

To find the period of oscillation for a particle executing simple harmonic motion (SHM) given its maximum speed and maximum acceleration, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values:**
- Maximum speed (V_max) = 30 cm/s
- Maximum acceleration (a_max) = 60 cm/s²

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