A mass of 2kg is attached to the spring of spring constant `50Nm^(-1)`. The block is pulled to a distance of 5 cm from its equilibrium position at `x=0` on a horizontal frictionless surface from rest at t=0. Write the expression for its displacement at anytime t.

Explanation

To find the expression for the displacement of a mass attached to a spring undergoing simple harmonic motion (SHM), we can follow these steps:

### Step 1: Identify the parameters
Given:
- Mass \( m = 2 \, \text{kg} \)
- Spring constant \( k = 50 \, \text{N/m} \)
- Displacement from equilibrium (amplitude) \( A = 5 \, \text{cm} = 0.05 \, \text{m} \)

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