Two molecules of a gas have speeds of `9xx10^(6) ms^(-1)` and `1xx10^(6) ms^(-1)`, respectively. What is the root mean square speed of these molecules.

Explanation

To find the root mean square (RMS) speed of the two gas molecules, we can follow these steps:

### Step 1: Identify the speeds of the molecules
We are given the speeds of two molecules:
- Speed of the first molecule, \( v_1 = 9 \times 10^6 \, \text{m/s} \)
- Speed of the second molecule, \( v_2 = 1 \times 10^6 \, \text{m/s} \)

### Step 2: Use the formula for root mean square speed
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