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In a refrigerator one removes heat from ...

In a refrigerator one removes heat from a lower temperature and deposits to the surroundings at a higher temperature. In this process, mechanical work has to be done, which is provided by an electric motor. If the motor is of 1kW power and heat transferred from `-3^(@)` C to `27^(@)` C, find the heat taken out of the refrigerator per second assuming its efficiency is 50% of a perfect engine.

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To solve the problem, we need to follow these steps: ### Step 1: Convert Temperatures to Kelvin We have the temperatures given in degrees Celsius. We need to convert them to Kelvin: - For the sink temperature (T1): \[ T_1 = 27^\circ C = 27 + 273 = 300 \, K \] ...
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