Home
Class 11
MATHS
The set {x in R : 1 le x lt 2} be writ...

The set ` {x in R : 1 le x lt 2}` be written as `"……………"` .

Text Solution

AI Generated Solution

To express the set \( \{ x \in \mathbb{R} : 1 \leq x < 2 \} \) in interval notation, we follow these steps: 1. **Identify the bounds of the set**: The set is defined for \( x \) such that \( 1 \leq x < 2 \). This means that \( x \) can take values starting from 1 (inclusive) up to, but not including, 2. 2. **Use interval notation**: In interval notation, we represent the lower bound (1) with a square bracket [ ] to indicate that it is included in the set, and the upper bound (2) with a parenthesis ( ) to indicate that it is not included in the set. 3. **Write the interval**: Therefore, the interval can be written as \( [1, 2) \). ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SETS

    NCERT EXEMPLAR ENGLISH|Exercise TRUE AND FALSE|6 Videos
  • SETS

    NCERT EXEMPLAR ENGLISH|Exercise OBJECTIVE TYPE QUESTIONS|14 Videos
  • SEQUENCE AND SERIES

    NCERT EXEMPLAR ENGLISH|Exercise Match the comumms|2 Videos
  • STATISTICS

    NCERT EXEMPLAR ENGLISH|Exercise FILLERS|7 Videos

Similar Questions

Explore conceptually related problems

If A = {x in R : 0 lt x lt 4} and B = {x in R : 1 le x le 7} then find A Delta B .

If -1 le [2x^2 -3] lt 2 , then x belongs to

Knowledge Check

  • The solution set of -1 le 3+ 4x lt 23, x in W is

    A
    {0, 1, 2, 3, 4}
    B
    `{-1, 0, 1, 2,3,4}`
    C
    {0,1,2,3,4,5}
    D
    `{-1, 0,1,2,3,4,5}`
  • The solution of 2x - 5 le 5x lt 11, x in R is :

    A
    `{x : 3 le x lt (7)/(5), x in R}`
    B
    `{x : (-7)/(5) le x lt 3, x in R}`
    C
    `{x : (7)/(5) le x lt 3, x in R}`
    D
    `{x : 3 le x lt -(7)/(5), x in R}`
  • The solution set of 6 le -3 (2x-4) lt 12 , x in R is

    A
    `(0,1]`
    B
    `[1,0)`
    C
    `(0,1)`
    D
    `[0,1]`
  • Similar Questions

    Explore conceptually related problems

    Illustrate the set {x : -3 le x lt 0 or x gt 2, x in R} on a real number line.

    If A = {x in R : 0 lt x lt 1} and B = {y in R : -1 lt y lt 1} , then A xx B is the set of all points lying

    If cos x- sin x ge 1 and 0 le x le 2pi , then find the solution set for x .

    The solution set of -2+ 10x le 13x+ 10 lt 24+ 10x, x in Z is

    The solution set of -12 lt 4 -(3x)/(-5) le 2 , x in R is