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The ordered pair (5,2) belongs to the ...

The ordered pair `(5,2) ` belongs to the relation
`R={(x,y):y=x-5,x,y in Z}`

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To determine whether the ordered pair (5, 2) belongs to the relation \( R = \{(x, y) : y = x - 5, x, y \in \mathbb{Z}\} \), we will follow these steps: ### Step 1: Understand the Relation The relation \( R \) is defined such that for any ordered pair \( (x, y) \), the value of \( y \) must be equal to \( x - 5 \). This means that for any integer \( x \), we can find a corresponding integer \( y \) by subtracting 5 from \( x \). ### Step 2: Substitute the Values We need to check if the ordered pair \( (5, 2) \) satisfies the relation. Here, \( x = 5 \) and \( y = 2 \). ### Step 3: Calculate \( y \) using the Relation Using the relation \( y = x - 5 \): \[ y = 5 - 5 = 0 \] ### Step 4: Compare the Calculated \( y \) with Given \( y \) Now we compare the calculated value of \( y \) with the given value of \( y \) from the ordered pair: - Calculated \( y = 0 \) - Given \( y = 2 \) ### Step 5: Conclusion Since \( 0 \neq 2 \), the ordered pair \( (5, 2) \) does not satisfy the relation \( R \). Therefore, the ordered pair \( (5, 2) \) does not belong to the relation \( R \). ### Final Answer The ordered pair \( (5, 2) \) does not belong to the relation \( R \). ---

To determine whether the ordered pair (5, 2) belongs to the relation \( R = \{(x, y) : y = x - 5, x, y \in \mathbb{Z}\} \), we will follow these steps: ### Step 1: Understand the Relation The relation \( R \) is defined such that for any ordered pair \( (x, y) \), the value of \( y \) must be equal to \( x - 5 \). This means that for any integer \( x \), we can find a corresponding integer \( y \) by subtracting 5 from \( x \). ### Step 2: Substitute the Values We need to check if the ordered pair \( (5, 2) \) satisfies the relation. Here, \( x = 5 \) and \( y = 2 \). ...
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Knowledge Check

  • If A = {2,3,4,5,6) and R is a relation on set A defined by R= {(x, y): y=x+2, X, y in A} then

    A
    {(2,4), (3,5), (4, 6)}
    B
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    C
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    A
    `(5)/(24)`
    B
    `(5)/(2)`
    C
    `(29)/(8)`
    D
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  • Let A = {1,2,3,4,5,6} and R be the relation defined on A by R = {(x, y): x, y in A, x divides y}, then range of R is

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    B
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    C
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    D
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