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which one of the following is a poly...

which one of the following is a polynomial ?

A

`(x^(2))/(2)-(2)/(x^(2))`

B

`sqrt(2x)-1`

C

`x^(2)+(3x^(3//2))/(sqrtx)`

D

`(x-1)/(x+1)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given expressions is a polynomial, we need to evaluate each expression based on the definition of a polynomial. A polynomial is an algebraic expression that consists of terms with non-negative integer exponents. Let's analyze each option step by step: ### Step 1: Analyze the first expression: \( \frac{x^2}{2} - \frac{2}{x} \) - Rewrite \( \frac{2}{x} \) as \( 2x^{-1} \). - The term \( x^{-1} \) has a negative exponent, which is not allowed in polynomials. **Conclusion**: This expression is **not a polynomial**. ### Step 2: Analyze the second expression: \( \sqrt{2}x - 1 \) - Rewrite \( \sqrt{2}x \) as \( \sqrt{2}x^{1/2} \). - The exponent \( 1/2 \) is a fraction, which is not a non-negative integer. **Conclusion**: This expression is **not a polynomial**. ### Step 3: Analyze the third expression: \( \frac{x^2 + 3x^{3/2}}{\sqrt{x}} \) - Rewrite \( \sqrt{x} \) as \( x^{1/2} \). - The expression becomes \( \frac{x^2 + 3x^{3/2}}{x^{1/2}} \). - Simplifying gives us \( x^{2 - 1/2} + 3x^{3/2 - 1/2} = x^{3/2} + 3x^{1} \). - Both \( x^{3/2} \) and \( x^{1} \) contain a term with a fractional exponent. **Conclusion**: This expression is **not a polynomial**. ### Step 4: Analyze the fourth expression: \( \frac{x - 1}{x + 1} \) - This is a rational expression (a fraction). - Polynomials cannot have variables in the denominator. **Conclusion**: This expression is **not a polynomial**. ### Final Conclusion After analyzing all four expressions, none of them qualify as a polynomial. Therefore, the correct answer is that **none of the given expressions is a polynomial**.

To determine which of the given expressions is a polynomial, we need to evaluate each expression based on the definition of a polynomial. A polynomial is an algebraic expression that consists of terms with non-negative integer exponents. Let's analyze each option step by step: ### Step 1: Analyze the first expression: \( \frac{x^2}{2} - \frac{2}{x} \) - Rewrite \( \frac{2}{x} \) as \( 2x^{-1} \). - The term \( x^{-1} \) has a negative exponent, which is not allowed in polynomials. ...
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