Factorize : `(x-2y)^3+(2y-3z)^3+(3z-x)^3`

Explanation

To factorize the expression \((x-2y)^3 + (2y-3z)^3 + (3z-x)^3\), we can use the identity for the sum of cubes. The identity states that:

\[ a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - ac - bc) \]

If \(a + b + c = 0\), then:

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