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If APB and CQD are two parallel lines, t...

If APB and CQD are two parallel lines, then the bisectors of the angles APQ, BPQ, CQP and PQD form Option1: a square Option2: a rhombus Option3: a rectangle Option4: any other parallelogram

A

a square

B

a rhombus

C

a rectangle

D

any other parallelogram

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The correct Answer is:
To solve the problem, we need to analyze the given information about the angles formed by the two parallel lines APB and CQD, and how their angle bisectors interact. ### Step-by-Step Solution: 1. **Identify the Angles**: We have two parallel lines, APB and CQD. The angles we are interested in are APQ, BPQ, CQP, and PQD. 2. **Use Properties of Parallel Lines**: Since APB and CQD are parallel, we know that: - Angle APQ is equal to angle PQD (alternate interior angles). - Therefore, we can write: \[ \angle APQ = \angle PQD \] 3. **Angle Bisectors**: The angle bisectors of angles APQ and PQD will create two new angles: - Let \( MPQ \) be the angle bisector of \( APQ \) and \( NQP \) be the angle bisector of \( PQD \). - Since \( \angle APQ = \angle PQD \), it follows that: \[ \angle MPQ = \angle NQP \] 4. **Establish Parallel Lines**: Since \( MPQ \) and \( NQP \) are equal and are both angle bisectors, we can conclude that: - \( MP \parallel QN \) (as they are corresponding angles). 5. **Consider the Other Angles**: Similarly, we can analyze angles CQP and BPQ: - By the same reasoning, we find that the angle bisectors of these angles will also be parallel: \[ PN \parallel MQ \] 6. **Forming a Parallelogram**: From the above steps, we have established that: - \( MP \parallel QN \) - \( PN \parallel MQ \) Thus, the figure formed by the bisectors \( MP, QN, PN, \) and \( MQ \) is a parallelogram. 7. **Check for Right Angles**: To determine if this parallelogram is a rectangle or a square, we need to check if any angle is 90 degrees. - Since angle CQD is 180 degrees, we can express it as: \[ \angle CQP + \angle DQP = 180^\circ \] - Dividing by 2 gives us: \[ \frac{1}{2} \angle CQP + \frac{1}{2} \angle DQP = 90^\circ \] - This means that the angles \( MQP \) and \( NQP \) are both 90 degrees. 8. **Conclusion**: Since we have established that all angles in the quadrilateral formed by the angle bisectors are right angles, we conclude that the shape is a square. ### Final Answer: The bisectors of angles APQ, BPQ, CQP, and PQD form a **square**.

To solve the problem, we need to analyze the given information about the angles formed by the two parallel lines APB and CQD, and how their angle bisectors interact. ### Step-by-Step Solution: 1. **Identify the Angles**: We have two parallel lines, APB and CQD. The angles we are interested in are APQ, BPQ, CQP, and PQD. 2. **Use Properties of Parallel Lines**: ...
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NCERT EXEMPLAR ENGLISH-QUADRILATERALS -LONG ANSWER TYPE QUESTIONS
  1. If APB and CQD are two parallel lines, then the bisectors of the angle...

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  2. A square is incribed in an isoceles right triangle, so that the square...

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  3. In a parallelogram ABCD, AB = 10 cm and AD = 6 cm. The bisector of ang...

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  4. P, Q , R and S are respectively the mid-points of the sides AB, BC, C...

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  5. ABCD is a rhombus and P, Q, R and S are wthe mid-points of the side...

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  6. P, Q, R and S are respectively the mid-points of sides AB, BC, CD and ...

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  7. If diagonal of a parallelogram bisects one of the angles of the para...

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  8. ABCD is a parallelogram in which P and Q are mid-points of opposite ...

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  9. ABCD is a quadrilateral in which AB||DC and AD = BC. Prove that angleA...

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  10. In figure, AB||DE, AB=DE, AC||DF and AC=DF. Prove that BC||EF and BC=E...

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  11. In A B C ,A D is the median through A and E is the mid-point of A D ....

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  12. Show that the quadrilateral, formed by joining the mid-points of the ...

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  13. In Figure, A B C D isa trapezium in which side A B is a parallel to si...

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  14. Prove that the quadrilateral formed by the bisectors of the angles of ...

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  15. P and Q are points on opposite sides AD and BC of a parallelogram ABCD...

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  16. ABCD is a rectangle in which diagonal BD bisects angle B. Show that AB...

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  17. In DeltaA B C, D, E and F are respectively the mid-points of sides AB...

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  18. Prove that the line segment joining the mid-points of the diagonals of...

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  19. P is the mid-point of the side CD of a parallelogram ABCD. A line thro...

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