The sides of a quadrilateral ABCD are `6` `cm`, `8` `cm`, `12` `cm` and `14` `cm` (taken in order), respectively and the angle between the first two sides is a right angle. Find its area.

Explanation

To find the area of quadrilateral ABCD with sides 6 cm, 8 cm, 12 cm, and 14 cm, where the angle between the first two sides (AB and BC) is a right angle, we can break the quadrilateral into two triangles: triangle ABC and triangle ACD.

### Step 1: Calculate the area of triangle ABC
Since triangle ABC has a right angle at B, we can use the formula for the area of a right triangle:
\[ \text{Area}_{ABC} = \frac{1}{2} \times \text{base} \times \text{height} \]
Here, AB = 6 cm (base) and BC = 8 cm (height).
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