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If two positive integers `m` and `n` are expressible in the form `m=p q^3` and `n=p^3q^2` , where `p ,\ q` are prime numbers, then HCF `(m ,\ n)=`

A

`pq`

B

`pq^(2)`

C

`p^(3)q^(3)`

D

`p^(2)q^(2)`

Text Solution

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The correct Answer is:
To find the HCF (Highest Common Factor) of the two positive integers \( m \) and \( n \) expressed as \( m = p q^3 \) and \( n = p^3 q^2 \), where \( p \) and \( q \) are prime numbers, we can follow these steps: ### Step 1: Write down the expressions for \( m \) and \( n \) We have: - \( m = p q^3 \) - \( n = p^3 q^2 \) ### Step 2: Factorize \( m \) and \( n \) From the expressions, we can see: - For \( m \): The prime factorization is \( p^1 \cdot q^3 \) - For \( n \): The prime factorization is \( p^3 \cdot q^2 \) ### Step 3: Identify the common prime factors The common prime factors between \( m \) and \( n \) are \( p \) and \( q \). ### Step 4: Determine the minimum power of each common prime factor - For \( p \): The minimum power is \( \min(1, 3) = 1 \) - For \( q \): The minimum power is \( \min(3, 2) = 2 \) ### Step 5: Write the HCF using the common prime factors The HCF is obtained by multiplying the common prime factors raised to their minimum powers: \[ \text{HCF}(m, n) = p^{\min(1, 3)} \cdot q^{\min(3, 2)} = p^1 \cdot q^2 = p q^2 \] ### Conclusion Thus, the HCF of \( m \) and \( n \) is: \[ \text{HCF}(m, n) = p q^2 \]

To find the HCF (Highest Common Factor) of the two positive integers \( m \) and \( n \) expressed as \( m = p q^3 \) and \( n = p^3 q^2 \), where \( p \) and \( q \) are prime numbers, we can follow these steps: ### Step 1: Write down the expressions for \( m \) and \( n \) We have: - \( m = p q^3 \) - \( n = p^3 q^2 \) ### Step 2: Factorize \( m \) and \( n \) ...
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