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Which constant must be added and subtrac...

Which constant must be added and subtracted to solve the quadratic equation `9x^2+ 3/4x - sqrt2 = 0` by the method of completing the square?

A

`1/8`

B

`1/64`

C

`1/4`

D

`9/64`

Text Solution

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The correct Answer is:
To solve the quadratic equation \(9x^2 + \frac{3}{4}x - \sqrt{2} = 0\) by the method of completing the square, we need to determine the constant that must be added and subtracted. Here are the steps to find that constant: ### Step 1: Rewrite the equation We start with the equation: \[ 9x^2 + \frac{3}{4}x - \sqrt{2} = 0 \] To make completing the square easier, we can first isolate the quadratic and linear terms: \[ 9x^2 + \frac{3}{4}x = \sqrt{2} \] ### Step 2: Factor out the coefficient of \(x^2\) Next, we factor out the coefficient of \(x^2\) from the left side: \[ 9\left(x^2 + \frac{1}{12}x\right) = \sqrt{2} \] ### Step 3: Identify the coefficient of \(x\) Now, we need to complete the square for the expression inside the parentheses. The coefficient of \(x\) is \(\frac{1}{12}\). ### Step 4: Calculate half of the coefficient and square it To complete the square, we take half of the coefficient of \(x\) (which is \(\frac{1}{12}\)), square it, and find the constant to be added and subtracted: \[ \text{Half of } \frac{1}{12} = \frac{1}{24} \] Now, squaring it gives: \[ \left(\frac{1}{24}\right)^2 = \frac{1}{576} \] ### Step 5: Add and subtract the constant inside the parentheses We add and subtract this constant inside the parentheses: \[ 9\left(x^2 + \frac{1}{12}x + \frac{1}{576} - \frac{1}{576}\right) = \sqrt{2} \] This simplifies to: \[ 9\left(\left(x + \frac{1}{24}\right)^2 - \frac{1}{576}\right) = \sqrt{2} \] ### Step 6: Distribute the 9 Distributing the 9 gives: \[ 9\left(x + \frac{1}{24}\right)^2 - \frac{9}{576} = \sqrt{2} \] ### Step 7: Simplify the constant We can simplify \(\frac{9}{576}\): \[ \frac{9}{576} = \frac{1}{64} \] Thus, we rewrite the equation as: \[ 9\left(x + \frac{1}{24}\right)^2 - \frac{1}{64} = \sqrt{2} \] ### Conclusion The constant that must be added and subtracted to solve the quadratic equation by completing the square is: \[ \frac{1}{576} \]

To solve the quadratic equation \(9x^2 + \frac{3}{4}x - \sqrt{2} = 0\) by the method of completing the square, we need to determine the constant that must be added and subtracted. Here are the steps to find that constant: ### Step 1: Rewrite the equation We start with the equation: \[ 9x^2 + \frac{3}{4}x - \sqrt{2} = 0 \] To make completing the square easier, we can first isolate the quadratic and linear terms: ...
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