Find the roots of the following quadratic equations by the factorisation method.
`21x^(2)-2x+1/21=0`

Explanation

Given equation is `21x^(2)-2x+1/21=0`
On multiplying by 21 on both sides, we get
`441x^(2)-42x+1=0`
`441x^(2)-(21x+21x)+1=0` [by splitting the middle term]
`implies 441x^(2)-21x-21x+1=0`
`implies 21x(21x-1)-1(21x-1)=0`
`implies (21x-1)(21x-1)=0`
Now `21x-1implies x=1/21` and `21x-1=0`
` :. x=1/21`
Hence the roots of the equation `441x^(2)-42x+1=0` are `1/21` and `1/21`