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A natural number, when increased by 12, ...

A natural number, when increased by 12, becomes equal to 160 times its reciprocal. Find the number.

Text Solution

Verified by Experts

Let the natural number be `x`
According to the question
`x+12=160/x`
On multiplying by `x` on both sides, we get
`implies x^(2)+12x-160=0`
`x^(2)+(20x-8x)-160=0`
`implies x^(2)+20x-8x-160=0` [by factorisation method]
`impliesx(x+20)-8(x+20)=0`
`implies (x+20)(x-8)=0`
Now `x+20=0implies x=-20` which is not possible because natural number is always greater than zero and `x-8=0impliesx=8`.
Hence, the required natural number is 8.
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Knowledge Check

  • Assertion: A natural number, when increased by 12, equals 160 times its reciprocal. The number is 20. Reason: The roots of a quadratic equation ax^(2) +bx+c= 0 are given by the formula x= (-b +- sqrt(b^(2)-4ac))/(2a) .

    A
    Both assertion and reason are correct and reason is the correct explanation of assertion.
    B
    Both assertion and reason are correct but reason is not the correct explanation of assertion.
    C
    Assertion is correct but reason is incorrect
    D
    Assertion is incorrect but reason is correct
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