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In P Q R ,\ \ Q M|P R and P R^2-P Q^2=Q...

In ` P Q R ,\ \ Q M_|_P R` and `P R^2-P Q^2=Q R^2` . Prove that `Q M^2=P MxxM R`

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To prove that \( Q M^2 = P M \times M R \) in triangle \( PQR \) where \( Q M \perp P R \) and \( P R^2 - P Q^2 = Q R^2 \), we can follow these steps: ### Step 1: Understand the Given Information We have triangle \( PQR \) with \( Q M \) being perpendicular to \( P R \). This means that \( \angle Q M R = 90^\circ \). ### Step 2: Apply the Pythagorean Theorem From the given information, we know that: \[ ...
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