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The tangent to the circumcircle of an is...

The tangent to the circumcircle of an isosceles `DeltaABC` at A, in which AB= AC, is parallel to BC.

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To solve the problem, we need to show that the tangent to the circumcircle of isosceles triangle ABC at point A is parallel to side BC. Here’s a step-by-step solution: ### Step 1: Understand the Given Information We have an isosceles triangle ABC where AB = AC. The tangent at point A on the circumcircle of triangle ABC is denoted as line XY. We need to prove that line XY is parallel to line BC. **Hint:** Identify the properties of isosceles triangles and the concept of tangents to circles. ### Step 2: Draw the Diagram ...
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