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If cos(theta+phi)= mcos(theta-phi), then...

If `cos(theta+phi)= mcos(theta-phi)`, then prove that `tan theta=(1-m)/(1+m)cotphi`.

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To prove that \( \tan \theta = \frac{1 - m}{1 + m} \cot \phi \) given that \( \cos(\theta + \phi) = m \cos(\theta - \phi) \), we will follow these steps: ### Step 1: Start from the given equation We have: \[ \cos(\theta + \phi) = m \cos(\theta - \phi) \] ...
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