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Given xgt 0, then value of f(x)=-3cossqr...

Given x`gt` 0, then value of `f(x)=-3cossqrt(3+x+x^(2))` lie in the interval ….. .

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To find the interval in which the function \( f(x) = -3 \cos(\sqrt{3 + x + x^2}) \) lies for \( x > 0 \), we can follow these steps: ### Step 1: Define the function We start with the function: \[ f(x) = -3 \cos(\sqrt{3 + x + x^2}) \] ...
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