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If none of the digits 3, 5, 7, 8, 9 be r...

If none of the digits `3, 5, 7, 8, 9` be repeated, how many different numbers greater than 7000 can be formed with them?

A

190

B

192

C

180

D

185

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how many different numbers greater than 7000 can be formed using the digits 3, 5, 7, 8, and 9 without repetition, we will break it down into two cases: forming four-digit numbers and five-digit numbers. ### Step-by-Step Solution: **Step 1: Identify the digits available.** The digits we can use are 3, 5, 7, 8, and 9. **Step 2: Consider four-digit numbers greater than 7000.** For a four-digit number to be greater than 7000, the first digit must be either 7, 8, or 9. - **Case 1: First digit is 7.** - Remaining digits: 3, 5, 8, 9 (4 options left). - Second digit can be any of the remaining 4 digits. - Third digit can be any of the remaining 3 digits. - Fourth digit can be any of the remaining 2 digits. The total combinations for this case: \[ 1 \times 4 \times 3 \times 2 = 24 \] - **Case 2: First digit is 8.** - Remaining digits: 3, 5, 7, 9 (4 options left). The total combinations for this case: \[ 1 \times 4 \times 3 \times 2 = 24 \] - **Case 3: First digit is 9.** - Remaining digits: 3, 5, 7, 8 (4 options left). The total combinations for this case: \[ 1 \times 4 \times 3 \times 2 = 24 \] Adding all cases together for four-digit numbers: \[ 24 + 24 + 24 = 72 \] **Step 3: Consider five-digit numbers.** Any five-digit number formed with the digits 3, 5, 7, 8, and 9 will be greater than 7000 since the smallest five-digit number using these digits starts with 3, which is still greater than 7000. The total combinations for five-digit numbers: \[ 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \] **Step 4: Combine the results.** The total number of different numbers greater than 7000 is the sum of the four-digit and five-digit numbers: \[ 72 + 120 = 192 \] ### Final Answer: The total number of different numbers greater than 7000 that can be formed using the digits 3, 5, 7, 8, and 9 without repetition is **192**. ---

To solve the problem of how many different numbers greater than 7000 can be formed using the digits 3, 5, 7, 8, and 9 without repetition, we will break it down into two cases: forming four-digit numbers and five-digit numbers. ### Step-by-Step Solution: **Step 1: Identify the digits available.** The digits we can use are 3, 5, 7, 8, and 9. **Step 2: Consider four-digit numbers greater than 7000.** ...
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