Write the first three terms of the AP's, when a and d are as given below
(i) `a=(1)/(2), d= -(1)/(6) " " `
(ii) `a= -5, d= -3`

Explanation

(i) Given that, first term (a)`=(1)/(2)` and common difference (d)` = -(1)/(6)`
` :' `nth term of an AP, `T_(n)=a+(n-1)d`
` :.` Second term of an AP, `T_(2)=a+d=(1)/(2)-(1)/(6)=(2)/(6)=(1)/(3)`
and third term of an AP, `T_(3)=a+2d=(1)/(2)-(2)/(6)=(1)/(2)-(1)/(3)=(3-2)/(6)=(1)/(6)`
Hence, required three terms are`(1)/(2),(1)/(3),(1)/(6).`
(ii) Given that, first term (a)`= -5` and common difference (d)` = -3`
` :' `nth term of an AP, `T_(n)=a+(n-1)d`
` :.` Second term of an AP, `T_(2)=a+d= -5-3 = -8`
and third term of an AP, `T_(3)=a+2d= -5+2(-3)= -5-6= -11`
Hence, required three terms are` -5, -8, -11.`
(iii) Given that, first term (a)`=sqrt(2)` and common difference (d)` = (1)/(sqrt(2))`
` :' `nth term of an AP, `T_(n)=a+(n-1)d`
` :.` Second term of an AP, `T_(2)=a+d=sqrt(2)+(1)/(sqrt(2))=(2+1)/(sqrt(2))=(3)/(sqrt(2))`
and third term of an AP, `T_(3)=a+2d=sqrt(2)+(2)/(sqrt(2))=(2+2)/(sqrt(2))=(4)/(sqrt(2))`
Hence, required three terms are`sqrt(2),(3)/(sqrt(2)),(4)/(sqrt(2)).`