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Evaluate sum(n=1)^(13)(i^n+i^(n+1)), whe...

Evaluate `sum_(n=1)^(13)(i^n+i^(n+1)),` where `n in Ndot`

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To evaluate the expression \( \sum_{n=1}^{13} (i^n + i^{n+1}) \), we can follow these steps: ### Step 1: Rewrite the Summation We can rewrite the expression inside the summation: \[ i^n + i^{n+1} = i^n + i \cdot i^n = (1 + i) i^n \] Thus, the summation becomes: ...
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