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An integer `m` is said to be related to another integer `n` if `m` is a multiple of `n` . Check if the relation is symmetric, reflexive and transitive.

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To determine if the relation defined by "an integer \( m \) is related to another integer \( n \) if \( m \) is a multiple of \( n \)" is symmetric, reflexive, and transitive, we will analyze each property step by step. ### Step 1: Define the Relation Let \( R \) be the relation defined as: \[ R = \{ (m, n) \mid m, n \in \mathbb{Z} \text{ and } m \text{ is a multiple of } n \} \] This means there exists some integer \( k \) such that: \[ m = k \cdot n \] where \( k \) is a natural number. ### Step 2: Check Reflexivity A relation is reflexive if every element is related to itself. We need to check if \( m \) is related to \( m \): - For any integer \( m \), we can write: \[ m = 1 \cdot m \] Here, \( k = 1 \) is a natural number. - Since \( m \) is a multiple of itself, the relation is reflexive. ### Step 3: Check Symmetry A relation is symmetric if whenever \( m \) is related to \( n \), then \( n \) is also related to \( m \). We need to check: - Assume \( m \) is related to \( n \), which means: \[ m = k \cdot n \] for some natural number \( k \). - To check for symmetry, we need to see if \( n \) is related to \( m \). This would mean: \[ n = \frac{1}{k} \cdot m \] - However, \( \frac{1}{k} \) is not a natural number (it is a rational number), which means \( n \) cannot be expressed as a multiple of \( m \) in the context of natural numbers. - Therefore, the relation is **not symmetric**. ### Step 4: Check Transitivity A relation is transitive if whenever \( m \) is related to \( n \) and \( n \) is related to \( o \), then \( m \) is also related to \( o \). We need to check: - Let \( m \) be related to \( n \) and \( n \) be related to \( o \): - \( m = k \cdot n \) for some natural number \( k \) - \( n = l \cdot o \) for some natural number \( l \) - Substituting the second equation into the first gives: \[ m = k \cdot (l \cdot o) = (k \cdot l) \cdot o \] - Since the product \( k \cdot l \) is also a natural number, \( m \) is a multiple of \( o \). - Therefore, the relation is **transitive**. ### Conclusion - The relation is **reflexive**. - The relation is **not symmetric**. - The relation is **transitive**. ### Summary The relation defined by "an integer \( m \) is related to another integer \( n \) if \( m \) is a multiple of \( n \)" is reflexive and transitive but not symmetric.

To determine if the relation defined by "an integer \( m \) is related to another integer \( n \) if \( m \) is a multiple of \( n \)" is symmetric, reflexive, and transitive, we will analyze each property step by step. ### Step 1: Define the Relation Let \( R \) be the relation defined as: \[ R = \{ (m, n) \mid m, n \in \mathbb{Z} \text{ and } m \text{ is a multiple of } n \} \] This means there exists some integer \( k \) such that: \[ m = k \cdot n \] where \( k \) is a natural number. ...
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