First a set of n equal resistors of R each are connected in series to a battery of emf E and internal resistance R. A current I is observed to flow. Then, the n resistors are connected in parallel to the same battery. It is observed that the current is increased 10 times. What is 'n'?

Explanation

To solve the problem, we need to analyze the two scenarios given: when the resistors are connected in series and when they are connected in parallel.

### Step-by-Step Solution:

1. **Identify the Series Connection:**
When \( n \) resistors of resistance \( R \) are connected in series, the total resistance \( R_s \) is given by:
\[
R_s = R + nR = (n + 1)R
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