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Two identical current carrying coaxial l...

Two identical current carrying coaxial loops, carry current I in an opposite sense. A simple amperian loop passes through both of them once. Calling the loop as C,

A

`ointB.dl=2 mu_(0)I`

B

The value of `ointB.dl ` is independent of sense of C.

C

There may be z point of C where, B and dl are perpendicular

D

B vanishes everywhere on C.

Text Solution

Verified by Experts

The correct Answer is:
B, C
Applying the ampere's circuital law, we have
`oint=B.dl=mu_(0)(I-I)=0` (because current is in opposite sence).
Also, there may be a point on C where B and dl are perpendicular and hence,
`underset(c)ointB.dl=0`.
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