A proton, a neutron, an electron and an `alpha`-particle have same energy. Then their de-Broglie wavelengths compare as

Options

A. `lamda_(p)=lamda_(n)gtlamda_(e)gtlamda_(alpha)`
B. `lamda_(alpha)ltlamda_(p)=lamda_(n)gtlamda_(e)`
C. `lamda_(e)ltlamda_(p)=lamda_(n)gtlamda_(alpha)`
D. `lamda_(e)=lamda_(p)=lamda_(n)=lamda_(alpha)`

Explanation

To solve the problem of comparing the de-Broglie wavelengths of a proton, neutron, electron, and alpha particle with the same energy, we can follow these steps:

### Step 1: Understand the de-Broglie wavelength formula
The de-Broglie wavelength (λ) of a particle is given by the formula:
\[ \lambda = \frac{h}{p} \]
where \( h \) is Planck's constant and \( p \) is the momentum of the particle.
...