Home
Class 12
PHYSICS
An electron is moving with an initial ve...

An electron is moving with an initial velocity `vecv=v_(0)hati` and is in a magnetic field `vecB=B_(0)hatj`. Then it's de-Broglie wavelength

A

remains constant

B

increases with time

C

decreases with time

D

increases and decreases periodically

Text Solution

AI Generated Solution

To find the de-Broglie wavelength of an electron moving in a magnetic field, we can follow these steps: ### Step 1: Understand the Initial Conditions The electron has an initial velocity given by: \[ \vec{v} = v_0 \hat{i} \] and it is in a magnetic field: ...
Promotional Banner

Topper's Solved these Questions

  • DUAL NATURE OF RADIATION AND MATTER

    NCERT EXEMPLAR ENGLISH|Exercise VERY SHORT ANSWER TYPE QUESTIONS|5 Videos
  • DUAL NATURE OF RADIATION AND MATTER

    NCERT EXEMPLAR ENGLISH|Exercise SHORT ANSWER TYPE QUESTIONS|6 Videos
  • CURRENT ELECTRICITY

    NCERT EXEMPLAR ENGLISH|Exercise Very Short Answer Type Question.|20 Videos
  • ELECTRIC CHARGES AND FIELD

    NCERT EXEMPLAR ENGLISH|Exercise Long Answer Type Question|6 Videos

Similar Questions

Explore conceptually related problems

An electron (mass m) with an initial velocity vecv=v_(0)hati is in an electric field vecE=E_(0)hatj . If lambda_(0)=h//mv_(0) . It's de-broglie wavelength at time t is given by

An electron (mass m) with initial velocity vecv = v_0 hati + 2v_0 hatj is in an electric field vecE = E_0 hatk . If lamda_0 is initial de-Broglie wavelength of electron, its de-Broglie wave length at time t is given by :

An electron (mass m) with an initial velocity v=v_(0)hat(i)(v_(0)gt0) is in an electric field E=-E_(0)hat(l)(E_(0)="constant"gt0) . Its de-Broglie wavelength at time t is given by

An electron (mass m) with an initial velocity v=v_(0)hat(i)(v_(0)gt0) is in an electric field E=-E_(0)hat(l)(E_(0)="constant"gt0) . Its de-Broglie wavelength at time t is given by

An electron (mass m ) with initival velocity vecv = v_(0) hati + v_(0) hatj is the an electric field vecE = - E_(0)hatk . It lambda_(0) is initial de - Broglie wavelength of electron, its de-Broglie wave length at time t is given by :

An electron (mass m) with initial velocity bar(v) = -v_(0)hati + 3v_(0)hatk is in an electric field hatE = = 2E_(0)hatj . If lamda_(0) is initial de-Broglie wavelength of electron, its de-Broglie wave length at time t is given by :

An electron projectes with velocity vecv=v_(0)hati in the electric field vecE=E_(0)hatj . There the path followed by the electron E_(0) .

An electron is moving initially with velocity v_o hati+v_ohatj in uniform electric field vec E=-E_0 hatk . If initial wavelength of electron is lambda_0 and mass of electron is m. Find wavelength of electron as a function of time.

A charged particle of specific charge alpha moves with a velocity vecv=v_0hati in a magnetic field vecB=(B_0)/(sqrt2)(hatj+hatk) . Then (specific charge=charge per unit mass)

An electron of mass m with an initial velocity vec(v) = v_(0) hat (i) (v_(0) gt 0) enters an electric field vec(E ) =- E_(0) hat (j) (E_(0) = constant gt 0) at t = 0 . If lambda_(0) is its de - Broglie wavelength initially, then its de - Broglie wavelength at time t is