The de-broglie wavelength of a photon is twice the de-broglie wavelength of an electron. The speed of the electron is `v_(e)=c/100`. Then

Options

A. `(E_(e))/(E_(p))=10^(-4)`
B. `(E_(e))/(E_(p))=10^(-2)`
C. `(p_(e))/(m_(e)c)=10^(-2)`
D. `(p_(e))/(m_(e)c)=10^(-4)`

Explanation

To solve the problem, we need to find the ratio of the energy of an electron to the energy of a photon, given that the de Broglie wavelength of a photon is twice that of an electron, and the speed of the electron is \( v_e = \frac{c}{100} \).

### Step-by-step Solution:

1. **Define the de Broglie Wavelengths**:
- The de Broglie wavelength of the electron (\( \lambda_e \)) is given by:
\[
\lambda_e = \frac{h}{m_e v_e}
...