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Assuming an electron is confined to a 1n...

Assuming an electron is confined to a `1nm` wide region, find the wavelength in momentum using Heisenberg Uncertainty principal `(Deltax Deltap~~h)`. You can assume the uncertainty in position `Deltax` and `1nm`. Assuming `p~=Deltap`, find the energy of the electron in electron volts.

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To solve the problem step by step, we will use the Heisenberg Uncertainty Principle and some basic physics equations. ### Step 1: Understand the Heisenberg Uncertainty Principle The Heisenberg Uncertainty Principle states that the product of the uncertainty in position (Δx) and the uncertainty in momentum (Δp) is approximately equal to the reduced Planck's constant (ħ): \[ \Delta x \cdot \Delta p \approx \hbar \] where \(\hbar = \frac{h}{2\pi}\) and \(h = 6.626 \times 10^{-34} \, \text{Js}\). ...
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Using Heisenberg's uncertainty principle, calculate the uncertainty in velocity of an electron if uncertainty in its position is 10^(-11)m Given, h =6.6 xx 10^(-14)kg m^2s^(-1), m=9.1 xx 10^(-31)kg