Home
Class 12
PHYSICS
Two particles A and B of de-broglie wave...

Two particles A and B of de-broglie wavelength `lambda_(1) and lambda_(2)` combine to from a particle C. The process conserves momentum. Find the de-Broglie wavelength of the particle C. (The motion is one dimensional).

Text Solution

AI Generated Solution

To find the de-Broglie wavelength of particle C formed by the combination of two particles A and B with de-Broglie wavelengths λ₁ and λ₂, we will use the principle of conservation of momentum. Let's analyze the situation step by step. ### Step 1: Understand the de-Broglie wavelength The de-Broglie wavelength (λ) of a particle is given by the formula: \[ \lambda = \frac{h}{p} \] where \( h \) is Planck's constant and \( p \) is the momentum of the particle. ...
Promotional Banner

Topper's Solved these Questions

  • DUAL NATURE OF RADIATION AND MATTER

    NCERT EXEMPLAR ENGLISH|Exercise LONG ANSWER TYPE QUESTION|5 Videos
  • DUAL NATURE OF RADIATION AND MATTER

    NCERT EXEMPLAR ENGLISH|Exercise VERY SHORT ANSWER TYPE QUESTIONS|5 Videos
  • CURRENT ELECTRICITY

    NCERT EXEMPLAR ENGLISH|Exercise Very Short Answer Type Question.|20 Videos
  • ELECTRIC CHARGES AND FIELD

    NCERT EXEMPLAR ENGLISH|Exercise Long Answer Type Question|6 Videos

Similar Questions

Explore conceptually related problems

The de Broglie wavelength associated with particle is

Two particles A and B have de-Broglie's wavelength 30Å combined to from a single particle C. Momentum is conserved in this processs. The possible de-Broglile's wavelength of C is (the motion in one dimensional)

For particles having same K.E., the de-Broglie wavelength is

De Broglie wavelength lambda is proportional to

A particle is droped from a height H. The de-broglie wavelength of the particle as a function of height is proportional to

A particle is droped from a height H. The de-broglie wavelength of the particle as a function of height is proportional to

Two particles of de-broglie wavelength lamda_(x) and lamda_(y) are moving in opposite direction. Find debroglie wavelength after perfectly inelastic collision:

The de-Broglie wavelength of a particle with mass 1 g and velocity 100 m//sec is.

A particle ‘P’ is formed due to a completely inelastic collision of particles ‘x’ and ‘y’ having de-Broglie wavelength lambda_(x) and lambda_(y) respectively. If x and y were moving in opposite directions, then the de-Broglie wavelength of ‘P’ is:

If the kinetic energy of a particle is increased by 16 times, the percentage change in the de Broglie wavelength of the particle is