`S` is any point on side QR of a `Delta PQR`. Show that ` PQ + QR+RP gt 2 PS ` .

Explanation

To prove that \( PQ + QR + RP > 2PS \) for any point \( S \) on side \( QR \) of triangle \( PQR \), we can follow these steps:

### Step 1: Consider Triangle \( PQS \)
In triangle \( PQS \), we apply the triangle inequality, which states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side. Here, we have:

\[ PQ + QS > PS \tag{1} \]
...