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D is any point on side AC of a Delta ABC...

`D` is any point on side `AC` of a `Delta ABC` with `AB`= `AC` .Show that `CD lt BD`.

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To prove that \( CD < BD \) in triangle \( ABC \) where \( AB = AC \) and \( D \) is any point on side \( AC \), we can follow these steps: ### Step 1: Understand the triangle properties Given that \( AB = AC \), triangle \( ABC \) is an isosceles triangle. Therefore, the angles opposite the equal sides are equal. ### Step 2: Identify the angles Let: - \( \angle ABC = \alpha \) ...
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