The probability that a non-leap your selected at random will contain 53 Sunday is

Options

A. `(1)/(7)`
B. `(2)/(7)`
C. `(3)/(7)`
D. `(5)/(7)`

Explanation

To find the probability that a non-leap year selected at random will contain 53 Sundays, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the total number of days in a non-leap year**:
A non-leap year has 365 days.

2. **Calculate the number of weeks in a non-leap year**:
To find the number of weeks, we divide the total number of days by the number of days in a week (7 days).
\[ \text{Number of weeks} = \frac{365}{7} = 52 \text{ weeks} + 1 \text{ day} \]
This means there are 52 complete weeks and 1 extra day.

3. **Determine the extra day**:
The extra day can be any day of the week (Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, or Saturday).

4. **Calculate the probability that the extra day is a Sunday**:
The probability of the extra day being a Sunday is the number of favorable outcomes (which is 1, since only one day can be Sunday) divided by the total number of possible outcomes (which is 7, since there are 7 days in a week).
\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{1}{7} \]

5. **Conclusion**:
Therefore, the probability that a non-leap year will contain 53 Sundays is \(\frac{1}{7}\).

### Final Answer:
The probability that a non-leap year selected at random will contain 53 Sundays is \(\frac{1}{7}\).

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