A coin is tossed two times. Find the probability of getting atmost one head.

Explanation

The possible outcomes, If a coin is tossed 2 times is S={(HH),(TT),(HT),(TH)}
Let E=Event of getting at most one head ={(TT),(HT),(TH)}
n(E )=3
Hence, required probability=`(n(E ))/(n(S))=(3)/(4)`