Home
Class 11
PHYSICS
The velocity of a body of mass 2 kg as...

The velocity of a body of mass ` 2 kg ` as a function of t is given by ` upsilon(t) = 2t hati + t^(2) hatj ` Find the momentum and force acting on it at time `t = 2 s`.

Text Solution

AI Generated Solution

To solve the problem step by step, we will find the momentum and force acting on a body of mass 2 kg with the given velocity function \( \upsilon(t) = 2t \hat{i} + t^2 \hat{j} \) at time \( t = 2 \) seconds. ### Step 1: Find the velocity at \( t = 2 \) seconds The velocity function is given as: \[ \upsilon(t) = 2t \hat{i} + t^2 \hat{j} \] Substituting \( t = 2 \): ...
Promotional Banner

Topper's Solved these Questions

  • LAWS OF MOTION

    NCERT EXEMPLAR ENGLISH|Exercise Short answer type questions|6 Videos

  • LAWS OF MOTION

    NCERT EXEMPLAR ENGLISH|Exercise Long answer Type Questions|9 Videos

  • LAWS OF MOTION

    NCERT EXEMPLAR ENGLISH|Exercise Mutiple Choice Questions (More than One Options)|6 Videos

  • KINETIC THEORY

    NCERT EXEMPLAR ENGLISH|Exercise Multiple Choice Questions (MCQs)|31 Videos

  • MECHANICAL PROPERTIES OF FLUIDS

    NCERT EXEMPLAR ENGLISH|Exercise Long Answer Type Questions|3 Videos

Similar Questions

Explore conceptually related problems

The velocity of an object is given by vecv = ( 6 t^(3) hati + t^(2) hatj) m//s . Find the acceleration at t = 2s.

The velocity of an object is given by vecv = ( 6 t^(3) hati + t^(2) hatj) m//s) . Find the acceleration at t = 2s.

The position (x) of a particle of mass 1 kg moving along x-axis at time t is given by (x=(1)/(2)t^(2)) metre. Find the work done by force acting on it in time interval from t=0 to t=3 s.

The position (x) of a particle of mass 1 kg moving along x-axis at time t is given by (x=(1)/(2)t^(2)) meter. Find the work done by force acting on it in time interval from t=0 to t=3 s.

The position (x) of a particle of mass 2 kg moving along x-axis at time t is given by x=(2t^(3)) metre. Find the work done by force acting on it in time interval t=0 to t=2 is :-

The time dependence of the position of a particle of mass m = 2 is given by vec(r) (t) = 2t hat(i) - 3 t^(2) hat(j) Its angular momentum, with respect to the origin, at time t = 2 is :

The time dependence of the position of a particle of mass m = 2 is given by vec(r) (t) = 2t hat(i) - 3 t^(2) hat(j) Its angular momentum, with respect to the origin, at time t = 2 is :

The velocity vector of the motion described by the position vector of a particle, r = 2t hati + t^(2) hatj is given by

The position time graph of a body of mass 2 kg is as given in What is the impulse on the body at t = 0 s and t = 4 s ? .

The momentum of a body in two perpendicular direction at any time 't' are given by P_(x) =2t^(2) + 6 and P_(y) = (3t^(2))/2 + 3 . The force acting on the body at t= 2 sec is