Two pea plants one with round green seeds (RRyy) and another with wrinkled yellow (YY) seeds produce `F_(1)`, progeny that have round, yellow (RrYy) seeds. When `F_(1)`, plants are selfed, the `F_(2)`, progeny will have new combination of characters. Choose the new combination from the following.
(i) Round, yellow
(ii) Round, green
(iii) Winkled, yellow
(iv) Wrinkled, green

Options

A. (i) and (ii)
B. (iv) Only
C. (ii) and (iii)
D. (i) and (iii)

Explanation

To solve the problem, we need to analyze the genetic cross between the two pea plants and determine the possible combinations of traits in the F2 generation.

### Step-by-Step Solution:

1. **Identify the Genotypes of the Parent Plants**:
- The first plant has round green seeds, which is represented by the genotype **RRyy** (homozygous dominant for round seeds and homozygous recessive for green color).
- The second plant has wrinkled yellow seeds, represented by the genotype **rrYY** (homozygous recessive for round seeds and homozygous dominant for yellow color).

2. **Determine the F1 Generation**:
- When these two plants are crossed, the F1 generation will inherit one allele from each parent for both traits.
- The resulting genotype of the F1 progeny will be **RrYy** (heterozygous for round seeds and heterozygous for yellow color).
- The phenotype of the F1 generation will be round yellow seeds since round (R) and yellow (Y) are dominant traits.

3. **Selfing the F1 Generation**:
- When the F1 plants (RrYy) are selfed (crossed with themselves), we can use a Punnett square to determine the possible combinations of alleles in the F2 generation.
- The gametes produced by the F1 plants will be: RY, Ry, rY, and ry.

4. **Constructing the Punnett Square**:
- The Punnett square for a dihybrid cross (RrYy x RrYy) will yield the following combinations:
- **RRYY** (Round, Yellow)
- **RRYy** (Round, Yellow)
- **RrYY** (Round, Yellow)
- **RrYy** (Round, Yellow)
- **rrYY** (Wrinkled, Yellow)
- **rrYy** (Wrinkled, Yellow)
- **Rryy** (Round, Green)
- **rryy** (Wrinkled, Green)

5. **Phenotypic Ratios**:
- The phenotypic ratio of the F2 generation from a dihybrid cross is typically 9:3:3:1.
- This means:
- 9 Round Yellow (RRYY, RRYy, RrYY, RrYy)
- 3 Round Green (Rryy)
- 3 Wrinkled Yellow (rrYY, rrYy)
- 1 Wrinkled Green (rryy)

6. **Identifying New Combinations**:
- The new combinations of traits that arise in the F2 generation are:
- Round Green (Rryy)
- Wrinkled Green (rryy)
- These combinations were not present in the parent generation.

### Conclusion:
The new combinations of characters in the F2 progeny will include:
- (ii) Round, green
- (iv) Wrinkled, green