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The more positive the value of E^(θ), th...

The more positive the value of `E^(θ)`, the greater is the trendency of the species to get reduced. Using the standard electrode potential of redox coples given below find out which of the following is the strongest oxidising agent.
`E^(θ)` values: `Fe^(3+)//Fe^(2+) = +0.77`
`I_(2)(s)//I^(-) = +0.54`,
`Cu^(2+)//Cu = +0.34, Ag^(+)//A = 0.80V`

A

`Fe^(3+)`

B

`I_(2)(s)`

C

`Cu^(2+)`

D

`Ag^(+)`

Text Solution

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The correct Answer is:
To determine which of the given redox couples is the strongest oxidizing agent, we need to analyze the standard electrode potential (E°) values provided. The stronger the oxidizing agent, the more positive its E° value will be, indicating a greater tendency to gain electrons (be reduced). ### Step-by-Step Solution: 1. **List the E° Values**: - For Fe³⁺/Fe²⁺: E° = +0.77 V - For I₂/I⁻: E° = +0.54 V - For Cu²⁺/Cu: E° = +0.34 V - For Ag⁺/Ag: E° = +0.80 V 2. **Identify the Oxidizing Agents**: - The oxidizing agent is the species that gets reduced (gains electrons). Therefore, we will consider the E° values as indicators of the strength of the oxidizing agents. - Higher E° values correspond to stronger oxidizing agents. 3. **Compare the E° Values**: - Compare the E° values: - Fe³⁺/Fe²⁺: +0.77 V - I₂/I⁻: +0.54 V - Cu²⁺/Cu: +0.34 V - Ag⁺/Ag: +0.80 V 4. **Determine the Strongest Oxidizing Agent**: - Among the given E° values, Ag⁺/Ag has the highest value of +0.80 V. - Therefore, Ag⁺ is the strongest oxidizing agent because it has the greatest tendency to get reduced. 5. **Conclusion**: - The strongest oxidizing agent among the given options is Ag⁺. ### Final Answer: **Ag⁺ is the strongest oxidizing agent.**
To determine which of the given redox couples is the strongest oxidizing agent, we need to analyze the standard electrode potential (E°) values provided. The stronger the oxidizing agent, the more positive its E° value will be, indicating a greater tendency to gain electrons (be reduced). ### Step-by-Step Solution: 1. **List the E° Values**: - For Fe³⁺/Fe²⁺: E° = +0.77 V - For I₂/I⁻: E° = +0.54 V - For Cu²⁺/Cu: E° = +0.34 V ...
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