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Identify the correct statements with ref...

Identify the correct statements with reference to the given reaction
`P_(4)+3OH^(-)+3H_(2)OtoPH_(3)+3H_(2)PO_(2)^(-)`

A

Phosphorus is undergoing reduction only

B

Phosphorus is undergoing oxidation only

C

Phosphorus is undergoing oxidation as well as reduction

D

Hydrogen is undergoing neither oxidation nor reduction

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will analyze the given reaction and determine the oxidation states of the elements involved. The reaction is: \[ P_4 + 3OH^- + 3H_2O \rightarrow PH_3 + 3H_2PO_2^- \] ### Step 1: Assign Oxidation States 1. **For \( P_4 \)**: In its elemental form, the oxidation state of phosphorus (P) is 0. 2. **For \( OH^- \)**: The oxidation state of oxygen (O) is -2 and hydrogen (H) is +1. 3. **For \( H_2O \)**: Each hydrogen (H) has an oxidation state of +1 and oxygen (O) is -2. 4. **For \( PH_3 \)**: Let the oxidation state of phosphorus be \( x \). The equation is: \[ x + 3(+1) = 0 \implies x + 3 = 0 \implies x = -3 \] So, the oxidation state of phosphorus in \( PH_3 \) is -3. 5. **For \( H_2PO_2^- \)**: Let the oxidation state of phosphorus be \( y \). The equation is: \[ y + 2(+1) + 2(-2) = -1 \implies y + 2 - 4 = -1 \implies y - 2 = -1 \implies y = +1 \] So, the oxidation state of phosphorus in \( H_2PO_2^- \) is +1. ### Step 2: Determine Changes in Oxidation States - **Phosphorus**: - Changes from 0 in \( P_4 \) to -3 in \( PH_3 \) (reduction). - Changes from 0 in \( P_4 \) to +1 in \( H_2PO_2^- \) (oxidation). - **Hydrogen**: - The oxidation state of hydrogen remains +1 in all species (no change). ### Step 3: Identify Oxidation and Reduction - **Oxidation**: Increase in oxidation state (loss of electrons). - **Reduction**: Decrease in oxidation state (gain of electrons). From the analysis: - Phosphorus is both oxidized (to +1 in \( H_2PO_2^- \)) and reduced (to -3 in \( PH_3 \)). - Hydrogen does not undergo any change in oxidation state. ### Conclusion Now, let's evaluate the statements: 1. **Phosphorus is undergoing reduction only**: **False** (it undergoes both oxidation and reduction). 2. **Phosphorus is undergoing oxidation only**: **False** (it undergoes both oxidation and reduction). 3. **Phosphorus is undergoing oxidation as well as reduction**: **True**. 4. **Hydrogen is undergoing neither oxidation nor reduction**: **True**. Thus, the correct statements are **3 and 4**.

To solve the problem, we will analyze the given reaction and determine the oxidation states of the elements involved. The reaction is: \[ P_4 + 3OH^- + 3H_2O \rightarrow PH_3 + 3H_2PO_2^- \] ### Step 1: Assign Oxidation States 1. **For \( P_4 \)**: In its elemental form, the oxidation state of phosphorus (P) is 0. 2. **For \( OH^- \)**: The oxidation state of oxygen (O) is -2 and hydrogen (H) is +1. 3. **For \( H_2O \)**: Each hydrogen (H) has an oxidation state of +1 and oxygen (O) is -2. ...
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