PbO and `PbO_(2)` react with HCl according to following chemical equations
`2PbO+4HCl to2PbCl_(2)+2H_(2)O`
`PbO_(2)+4HCl toPbCl_(2)+Cl_(2)+2H_(2)O`
Why do these compounds differ n their reactivity?

Explanation

To understand why PbO and PbO2 differ in their reactivity with HCl, we can analyze the reactions and the oxidation states of lead in both compounds. Here’s a step-by-step breakdown:

### Step 1: Analyze the Reactions
1. **Reaction of PbO with HCl:**
\[ 2 \text{PbO} + 4 \text{HCl} \rightarrow 2 \text{PbCl}_2 + 2 \text{H}_2\text{O} \]
- In PbO, lead (Pb) has an oxidation state of +2 (O is -2).
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