Home
Class 11
CHEMISTRY
Assertion (A) Redox couple is the combin...

Assertion (A) Redox couple is the combination of oxidised and reduced form of a substance involved in an oxidation or reduction half cell
Reason ( R) In the representation `E_(Fe^(-3+)//Fe^(2+))^(ϴ)` and `E_(Cu^(2+)//Cu)^(ϴ), Fe^(3+)//Fe^(2+)` and `Cu^(2+)//Cu` are redox couples

A

Both A and R are true and R is the correct explanation of A

B

Both A and R are true but R is not the correct explanation of A

C

A is true but R is false

D

Both A and R are false

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both the assertion (A) and the reason (R) provided in the question. ### Step-by-Step Solution: 1. **Understanding the Assertion (A)**: - The assertion states: "Redox couple is the combination of oxidized and reduced form of a substance involved in an oxidation or reduction half cell." - A redox couple indeed consists of two species: one in its oxidized form and the other in its reduced form. This pair participates in redox reactions, where one species gets oxidized (loses electrons) and the other gets reduced (gains electrons). 2. **Understanding the Reason (R)**: - The reason states: "In the representation `E_(Fe^(-3+)//Fe^(2+))^(ϴ)` and `E_(Cu^(2+)//Cu)^(ϴ)`, `Fe^(3+)//Fe^(2+)` and `Cu^(2+)//Cu` are redox couples." - This representation shows the standard electrode potentials of the redox couples. Here, `Fe^(3+)` and `Fe^(2+)` form a redox couple, as do `Cu^(2+)` and `Cu`. Each pair consists of an oxidized form and a reduced form. 3. **Evaluating the Truth of A and R**: - Both the assertion and the reason are true statements. The assertion correctly defines what a redox couple is, and the reason provides valid examples of redox couples. 4. **Determining the Relationship Between A and R**: - The reason (R) correctly explains the assertion (A) by providing specific examples of redox couples that fit the definition given in the assertion. 5. **Conclusion**: - Since both A and R are true, and R is the correct explanation of A, the correct answer is: **Both A and R are true, and R is the correct explanation of A.** ### Final Answer: Both A and R are true, and R is the correct explanation of A. ---

To solve the question, we need to analyze both the assertion (A) and the reason (R) provided in the question. ### Step-by-Step Solution: 1. **Understanding the Assertion (A)**: - The assertion states: "Redox couple is the combination of oxidized and reduced form of a substance involved in an oxidation or reduction half cell." - A redox couple indeed consists of two species: one in its oxidized form and the other in its reduced form. This pair participates in redox reactions, where one species gets oxidized (loses electrons) and the other gets reduced (gains electrons). ...
Promotional Banner

Topper's Solved these Questions

  • REDOX REACTIONS

    NCERT EXEMPLAR ENGLISH|Exercise LONG ANSWER TYPE QUESTIONS|6 Videos
  • REDOX REACTIONS

    NCERT EXEMPLAR ENGLISH|Exercise SHORT ANSWER TYPE QUESTIONS|12 Videos
  • ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES

    NCERT EXEMPLAR ENGLISH|Exercise Long Answer type question|6 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    NCERT EXEMPLAR ENGLISH|Exercise All Questions|45 Videos

Similar Questions

Explore conceptually related problems

Show that E_(Fe^(+3)//Fe^(+2))^(@) =3E_(Fe^(+3)//Fe)^(@)-2E_(Fe^(+2)//Fe)^(@)

E_(Cu^(2+)//Cu)^(@) =0.43V E_(Cu^(+)//Cu)^(@)=0.55V E_(Cu^(2+)//Cu^(+))^(@) =

State whether the following conversions are oxidation or reduction reactions. Cu^(2+) + 2e^(-) to Cu

Divide the following redox reactions into oxidation and reduction half reactions. Zn + Cu^(2+) to Zn&(2+) + Cu

Identify the following reactions as either oxidation or reduction : Fe^(3+) +e^(-) to Fe^(2+)

Given that E_(Cu^(2+)//Cu)^(0)=0.337 and E_(Cu^(+)//Cu^(2+))^(0)=-0.153V . then calculate E_(Cu^(+)//Cu)^(0)

(CU^(+) ((aq)) is unstable in solution and undergoes simultaneous oxidation and reduction, according to the reaction 2Cu_((aq))^(+) Cu_((aq))^(2+) +Cu_((s)) choose E^(@) for the above reaction if E_(Cu^(2+)//Cu^(@))= 0.34V and E_(Cu^(2+)//Cu^(+) )= 0.15V

Given that E_(Fe^(2+)//Fe)^(.)=-0.44V,E_(Fe^(3+)//Fe^(2+))^(@)=0.77V if Fe^(2+),Fe^(3+) and Fe solid are kept together then

E_(Cu^(2+)//Cu)^(@)=0.34V E_(Cu^(+)//Cu)^(@)=0.522V E_(Cu^(2+)//Cu^(+))^(@)=

E_(Cu^(2+)//Cu)^(@)=0.34V E_(Cu^(+)//Cu)^(@)=0.522V E_(Cu^(2+)//Cu^(+))^(@)=