Find angle `theta`, 0 < `theta` < `pi/2` , which increase twice as fast as sine

Explanation

To solve the problem of finding the angle \(\theta\) (where \(0 < \theta < \frac{\pi}{2}\)) that increases twice as fast as sine, we can follow these steps:

### Step 1: Set up the equation
We know that \(\theta\) increases twice as fast as \(\sin(\theta)\). This can be expressed mathematically as:
\[ \frac{d\theta}{dt} = 2 \frac{d}{dt}(\sin(\theta)) \]

...