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At what points on the curve x^2+y^2-2x-4...

At what points on the curve `x^2+y^2-2x-4y+1=0` , the tangents are parallel to the `y-a xi s ?`

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To find the points on the curve \( x^2 + y^2 - 2x - 4y + 1 = 0 \) where the tangents are parallel to the y-axis, we can follow these steps: ### Step 1: Rewrite the equation of the curve The given equation of the curve can be rewritten in a more recognizable form. We can complete the square for both \( x \) and \( y \). \[ x^2 - 2x + y^2 - 4y + 1 = 0 \] ...
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