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24. Find the intervals in which the foll...

24. Find the intervals in which the following function is (a) increasing and (b) decreasing `f(x)=2x^3+9x^2+12x-1`

A

`[-1,infty]`

B

`[-2,-1]`

C

`(-infty,-2)`

D

`[-1,1]`

Text Solution

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The correct Answer is:
To find the intervals in which the function \( f(x) = 2x^3 + 9x^2 + 12x - 1 \) is increasing or decreasing, we will follow these steps: ### Step 1: Differentiate the function We start by finding the derivative of the function \( f(x) \). \[ f'(x) = \frac{d}{dx}(2x^3 + 9x^2 + 12x - 1) \] Using the power rule, we differentiate each term: \[ f'(x) = 6x^2 + 18x + 12 \] ### Step 2: Set the derivative equal to zero Next, we find the critical points by setting the derivative equal to zero: \[ 6x^2 + 18x + 12 = 0 \] ### Step 3: Simplify the equation We can simplify this equation by dividing all terms by 6: \[ x^2 + 3x + 2 = 0 \] ### Step 4: Factor the quadratic equation Now, we will factor the quadratic equation: \[ (x + 1)(x + 2) = 0 \] ### Step 5: Find the critical points Setting each factor to zero gives us the critical points: \[ x + 1 = 0 \quad \Rightarrow \quad x = -1 \] \[ x + 2 = 0 \quad \Rightarrow \quad x = -2 \] ### Step 6: Determine the intervals The critical points divide the number line into intervals. We will test the intervals \( (-\infty, -2) \), \( (-2, -1) \), and \( (-1, \infty) \). ### Step 7: Test the intervals 1. **Interval \( (-\infty, -2) \)**: Choose \( x = -3 \) \[ f'(-3) = 6(-3)^2 + 18(-3) + 12 = 54 - 54 + 12 = 12 \quad (\text{positive}) \] 2. **Interval \( (-2, -1) \)**: Choose \( x = -1.5 \) \[ f'(-1.5) = 6(-1.5)^2 + 18(-1.5) + 12 = 13.5 - 27 + 12 = -1.5 \quad (\text{negative}) \] 3. **Interval \( (-1, \infty) \)**: Choose \( x = 0 \) \[ f'(0) = 6(0)^2 + 18(0) + 12 = 12 \quad (\text{positive}) \] ### Step 8: Conclusion From our tests, we conclude: - The function is **increasing** on the intervals \( (-\infty, -2) \) and \( (-1, \infty) \). - The function is **decreasing** on the interval \( (-2, -1) \). ### Final Answer (a) The function is increasing on the intervals \( (-\infty, -2) \) and \( (-1, \infty) \). (b) The function is decreasing on the interval \( (-2, -1) \). ---

To find the intervals in which the function \( f(x) = 2x^3 + 9x^2 + 12x - 1 \) is increasing or decreasing, we will follow these steps: ### Step 1: Differentiate the function We start by finding the derivative of the function \( f(x) \). \[ f'(x) = \frac{d}{dx}(2x^3 + 9x^2 + 12x - 1) \] ...
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