Home
Class 12
MATHS
The equation of normal to the curve y=ta...

The equation of normal to the curve y=tanx at (0,0) is ………………..

Text Solution

AI Generated Solution

To find the equation of the normal to the curve \( y = \tan x \) at the point \( (0, 0) \), we will follow these steps: ### Step 1: Identify the point on the curve The point given is \( (0, 0) \). We need to verify that this point lies on the curve \( y = \tan x \). ### Step 2: Differentiate the function To find the slope of the tangent line at the point \( (0, 0) \), we need to differentiate the function \( y = \tan x \). ...
Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    NCERT EXEMPLAR ENGLISH|Exercise OBJECTIVE TYPES QUESTIONS|25 Videos
  • APPLICATION OF INTEGRALS

    NCERT EXEMPLAR ENGLISH|Exercise Objective Type Questions|22 Videos

Similar Questions

Explore conceptually related problems

The equation of the normal to the curve y = sin x at (0,0) is

The equation to the normal to the curve y=sinx at (0,\ 0) is (a) x=0 (b) y=0 (c) x+y=0 (d) x-y=0

Write the equation of the normal to the curve y=cosx at (0,\ 1) .

The equation of the normal to the curve y^(4)=ax^(3) at (a, a) is

The equation of the normal to the curve y=x^(-x) at the point of its maximum is

Write the equation of the normal to the curve y=x+sinxcosx at x=pi/2 .

The equation of the normal to the curve y=x(2-x) at the point (2,\ 0) is (a) x-2y=2 (b) x-2y+2=0 (c) 2x+y=4 (d) 2x+y-4=0

The equation of the tangent to the curve y = e^(2x) at (0,1) is

The equation of the normal to the curve y= e^(-2|x|) at the point where the curve cuts the line x=-(1)/(2), is

The equation of the normal to the curve y=e^(-2|x|) at the point where the curve cuts the line x = 1//2 is