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The mean deviation of the data 3,10,10,4...

The mean deviation of the data 3,10,10,4,7,10,5 from the mean is

A

2

B

2.57

C

3

D

3.75

Text Solution

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The correct Answer is:
To find the mean deviation of the data set \(3, 10, 10, 4, 7, 10, 5\) from the mean, we will follow these steps: ### Step 1: Calculate the Mean (\( \bar{x} \)) The mean is calculated using the formula: \[ \bar{x} = \frac{\sum_{i=1}^{n} x_i}{n} \] where \( n \) is the number of observations and \( x_i \) are the data points. - Here, the data points are \(3, 10, 10, 4, 7, 10, 5\). - The number of observations \( n = 7 \). - The sum of the data points: \[ 3 + 10 + 10 + 4 + 7 + 10 + 5 = 49 \] - Now, substituting into the formula: \[ \bar{x} = \frac{49}{7} = 7 \] ### Step 2: Calculate the Deviations (\( d_i \)) Next, we need to find the absolute deviations from the mean for each data point: \[ d_i = |x_i - \bar{x}| \] - For \( x_1 = 3 \): \( d_1 = |3 - 7| = 4 \) - For \( x_2 = 10 \): \( d_2 = |10 - 7| = 3 \) - For \( x_3 = 10 \): \( d_3 = |10 - 7| = 3 \) - For \( x_4 = 4 \): \( d_4 = |4 - 7| = 3 \) - For \( x_5 = 7 \): \( d_5 = |7 - 7| = 0 \) - For \( x_6 = 10 \): \( d_6 = |10 - 7| = 3 \) - For \( x_7 = 5 \): \( d_7 = |5 - 7| = 2 \) ### Step 3: Calculate the Mean Deviation The mean deviation is calculated using the formula: \[ \text{Mean Deviation} = \frac{\sum_{i=1}^{n} d_i}{n} \] - Now, we sum the deviations: \[ \sum d_i = 4 + 3 + 3 + 3 + 0 + 3 + 2 = 18 \] - Now, substituting into the mean deviation formula: \[ \text{Mean Deviation} = \frac{18}{7} \approx 2.57 \] ### Final Answer The mean deviation of the data set \(3, 10, 10, 4, 7, 10, 5\) from the mean is approximately \(2.57\). ---

To find the mean deviation of the data set \(3, 10, 10, 4, 7, 10, 5\) from the mean, we will follow these steps: ### Step 1: Calculate the Mean (\( \bar{x} \)) The mean is calculated using the formula: \[ \bar{x} = \frac{\sum_{i=1}^{n} x_i}{n} \] where \( n \) is the number of observations and \( x_i \) are the data points. ...
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Knowledge Check

  • The mean deviation of the data 4,5,7,8,9,10,6 from the median is

    A
    1.87
    B
    2.32
    C
    1.71
    D
    2.45
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    A
    2
    B
    3
    C
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    D
    5
  • The mean deviation of the data 1,3,7,9,10,12 from the mean is

    A
    `(10)/(3)`
    B
    `(19)/(6)`
    C
    `(21)/(6)`
    D
    `(17)/(6)`
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